diketahui segitiga segitiga PQR siku-siku di Q jika QR 5 cm PQ = 10 cm nilai sin R adalah
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Jawab:
sin(R) = ²/₅√5
Penjelasan:
Diketahui:
ΔPQR siku di Q
PQ (a) = 10 cm
QR (b) = 5 cm
Ditanya: sin(R)
sin(R) = a/c
sin(R) = a/√(a²+b²)
sin(R) = 10/√(10²+5²)
sin(R) = 10/√(100+25)
sin(R) = 10/√(125)
sin(R) = 10/√(5³)
sin(R) = 10/√(5²·5)
sin(R) = 10/(√(5²)√5)
sin(R) = 10/(5√5)
sin(R) = (10√5)/(5√5·√5)
sin(R) = (10√5)/25
sin(R) = ²/₅√5
( x c v i )
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